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The partial fraction decomposition of
` \frac(16)((x-1)(x+1))`
can be written in the form of
` \frac(f(x))(x-1) +\frac(g(x))(x+1),` where
`f(x)=` ,
`g(x)=` .
`f(x)=` ,
`g(x)=` .
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